思路：先对 nums2 用单调栈求每个元素的下一个更大值，存入 Map 缓存；再遍历 nums1 直接查 Map 得结果。时间复杂度 O(len1 + len2)。
Tolley's team has even tried driving over one of their robots in a car. "We wanted to show it was soft and squishy enough. It can really suffer a lot of different abuses."
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Tony Jolliffe BBC。搜狗输入法下载对此有专业解读
# Extract files to disk