思路：① 找初始左边界：第一个 nums[i] nums[i+1]；② 找初始右边界：最后一个 nums[i] < nums[i-1]；③ 求 [left,right] 内 min、max；④ 向左扩展：nums[left-1] minVal 则 left--；⑤ 向右扩展：nums[right+1] < maxVal 则 right++。长度 = right - left + 1。
These are meaningful improvements, and some are clearly already underway. We'd love to see Google go further and retroactively audit existing impacted keys and notify project owners who may be unknowingly exposed, but honestly, that is a monumental task.，更多细节参见爱思助手下载最新版本
。旺商聊官方下载对此有专业解读
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"This was the worst mistake of my life."。业内人士推荐WPS下载最新地址作为进阶阅读
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